tree 552c4505c4a11bca5ca5b6b621053cb572e6a9b0
parent e7afb8c8980d8d87660b0b9135e4947e907b4aba
author Jesse Wilson <jessewilson@google.com> 1325879880 -0500
committer Jesse Wilson <jessewilson@google.com> 1325879880 -0500

Use 'new Label()' rather than 'Code.newLabel()' to make it clear that allocating a label is a free operation, not depending on the current state of the Code instance.